How to pass parameters to a PHP file in a cron job

This is just a quick tip but it annoyed the bejaysus out of me for about an hour. I was running the job in the following format:

00*** test_file.php?a=1&b=2&c=3

But an error was getting thrown saying that the input file, test_file.php?a=1&b=2&c=3, could not be found. With some help from the Google machine, I found that the correct format should be:

00*** test_file.php 1 2 3

And in your PHP file you can use the $argv variable to get at the paramter values

$a = argv[1];
$b = argv[2];
$c = argv[3];

And that should do the trick.